13. the presence of freckles (f) is dominant to no freckles (f). jake and his mom have freckles, but his…
13. the presence of freckles (f) is dominant to no freckles (f). jake and his mom have freckles, but his sister and dad do not have freckles. complete the punnett square that shows jakes family. dad mom phenotype probability (%) freckles: no freckles:
Answer
Explanation:
Step1: Determine parents' genotypes
Since no freckles (f) is recessive and Dad has no freckles, Dad's genotype is ff. Jake's sister has no freckles (ff), so she must get one f from each parent. Mom has freckles but gives an f to her daughter, so Mom's genotype is Ff.
Step2: Create Punnett square
Mom (Ff) can produce gametes F and f. Dad (ff) can only produce f.
| f | f | |
|---|---|---|
| F | Ff | Ff |
| f | ff | ff |
Step3: Calculate probabilities
There are 4 offspring possibilities. 2 are Ff (freckles) and 2 are ff (no freckles). Freckles probability: $\frac{2}{4}= 50%$ No - freckles probability: $\frac{2}{4}=50%$
Answer:
Freckles: 50% No Freckles: 50%