a colony of 4,050 bacteria doubles in size every 297 hours. what will the population be 594 hours from now…
a colony of 4,050 bacteria doubles in size every 297 hours. what will the population be 594 hours from now? bacteria
Answer
Explanation:
Step1: Determine number of doubling - periods
The bacteria doubles every 297 hours. The time elapsed is 594 hours. Calculate the number of doubling - periods $n=\frac{594}{297}$. $n = 2$
Step2: Calculate final population
The initial population $P_0 = 4050$. The population after $n$ doubling - periods is given by the formula $P = P_0\times2^n$. Substitute $P_0 = 4050$ and $n = 2$ into the formula. $P=4050\times2^2=4050\times4$ $P = 16200$
Answer:
16200