determining the effect of a new rate of change\nplant a:\nassume plant b received sunlight, and its rate of…

determining the effect of a new rate of change\nplant a:\nassume plant b received sunlight, and its rate of change was 1.6 inches a week instead of 1.4 inches per week. would it be taller at 6 weeks?\nno. it will be shorter.\nno. it will be the same height.\nyes. it will be 0.3 inches taller.\nyes. it will be 4.5 inches taller.\nplant b:\nweeks height (in)\n2 7.3\n3 8.7\n4 10.1
Answer
Answer:
Yes. It will be 1.2 inches taller.
Explanation:
Step1: Find initial height of Plant B
We can find the initial - height of Plant B using the slope - intercept form $y = mx + b$. The slope $m$ (rate of change) for the initial data of Plant B can be calculated using two points $(x_1,y_1)=(2,7.3)$ and $(x_2,y_2)=(3,8.7)$. The slope $m=\frac{y_2 - y_1}{x_2 - x_1}=\frac{8.7 - 7.3}{3 - 2}=1.4$. Using the point - slope form $y - y_1=m(x - x_1)$ with the point $(2,7.3)$ and $m = 1.4$, we have $y-7.3 = 1.4(x - 2)$. When $x = 0$, $y=7.3-1.4\times2=7.3 - 2.8 = 4.5$.
Step2: Calculate height of Plant B with initial rate at 6 weeks
Using the equation $y=mx + b$ with $m = 1.4$ and $b = 4.5$ and $x = 6$, we get $y_1=1.4\times6+4.5=8.4 + 4.5=12.9$.
Step3: Calculate height of Plant B with new rate at 6 weeks
With a new rate of change $m = 1.6$ and $b = 4.5$ and $x = 6$, we use the equation $y=mx + b$. So $y_2=1.6\times6+4.5=9.6+4.5 = 14.1$.
Step4: Find the difference in heights
The difference $\Delta y=y_2 - y_1=14.1-12.9 = 1.2$. So Plant B will be 1.2 inches taller.