a dihybrid cross is created from plants that are heterozygous for both round seeds and yellow seed color…

a dihybrid cross is created from plants that are heterozygous for both round seeds and yellow seed color. what is the ratio of offspring that have round seeds and yellow seed color?\n1:16\n3:16\n9:16\n16:16

a dihybrid cross is created from plants that are heterozygous for both round seeds and yellow seed color. what is the ratio of offspring that have round seeds and yellow seed color?\n1:16\n3:16\n9:16\n16:16

Answer

Explanation:

Step1: Determine allele - combinations

Let R represent the dominant allele for round seeds and r for wrinkled seeds; Y for yellow seeds and y for green seeds. The parents are RrYy. Using the Punnett - square method or the product rule, we consider the independent assortment of the two genes.

Step2: Analyze each gene separately

For the seed - shape gene (Rr x Rr), the probability of getting a round - seeded offspring (RR or Rr) is $\frac{3}{4}$ since the genotypic ratio is 1 RR : 2 Rr : 1 rr. For the seed - color gene (Yy x Yy), the probability of getting a yellow - seeded offspring (YY or Yy) is $\frac{3}{4}$ since the genotypic ratio is 1 YY : 2 Yy : 1 yy.

Step3: Use the product rule

Since the two traits assort independently, the probability of getting an offspring with both round seeds and yellow seeds is the product of the probabilities of each trait. So, $P=\frac{3}{4}\times\frac{3}{4}=\frac{9}{16}$.

Answer:

C. 9:16