in a dihybrid cross for round and yellow seeds (rryy x rryy), what is the probability of having green and…

in a dihybrid cross for round and yellow seeds (rryy x rryy), what is the probability of having green and wrinkled seeds? key: r = round r = wrinkled y = yellow y = green 1:16 3:16 8:16 9:16

in a dihybrid cross for round and yellow seeds (rryy x rryy), what is the probability of having green and wrinkled seeds? key: r = round r = wrinkled y = yellow y = green 1:16 3:16 8:16 9:16

Answer

Answer:

A. 1:16

Explanation:

Step1: Determine allele - combinations for each parent

Each RrYy parent can produce 4 types of gametes: RY, Ry, rY, ry.

Step2: Set up a Punnett - square

A Punnett - square for a dihybrid cross (4x4) has 16 possible offspring combinations.

Step3: Identify the genotype for green and wrinkled

The genotype for green and wrinkled seeds is rryy.

Step4: Count the number of rryy genotypes

In a RrYy x RrYy cross, only 1 out of 16 offspring has the rryy genotype. So the probability is 1:16.