a farmer feeds a cow 9,724 milligrams of an antibiotic. every hour, 50% of the drug breaks down in the cows…

a farmer feeds a cow 9,724 milligrams of an antibiotic. every hour, 50% of the drug breaks down in the cows body. how much will be left in 6 hours? if necessary, round your answer to the nearest tenth. milligrams
Answer
Explanation:
Step1: Identify the decay - formula
The formula for exponential decay is $A = A_0(1 - r)^t$, where $A_0$ is the initial amount, $r$ is the rate of decay, and $t$ is the time. Here, $A_0=9724$ mg, $r = 0.5$, and $t = 6$.
Step2: Substitute the values into the formula
$A=9724\times(1 - 0.5)^6$. First, calculate $(1 - 0.5)^6$. Since $1-0.5 = 0.5$, then $(0.5)^6=0.5\times0.5\times0.5\times0.5\times0.5\times0.5=\frac{1}{64}=0.015625$.
Step3: Calculate the final amount
$A = 9724\times0.015625$. $9724\times0.015625=\frac{9724}{64}=151.9375$. Rounding to the nearest tenth, we get $151.9$.
Answer:
$151.9$