the flowchart below shows the three generations of a cross between a pea plant that has yellow pods and a…

the flowchart below shows the three generations of a cross between a pea plant that has yellow pods and a pea plant that has green pods. green pods are the dominant trait. the flowchart is missing the labels that describe the traits.\n\nin which squares should the phrase \green pods\ appear?\n\na and d only\nb and e only\na, c, and d only\na, b, c, d, and e

the flowchart below shows the three generations of a cross between a pea plant that has yellow pods and a pea plant that has green pods. green pods are the dominant trait. the flowchart is missing the labels that describe the traits.\n\nin which squares should the phrase \green pods\ appear?\n\na and d only\nb and e only\na, c, and d only\na, b, c, d, and e

Answer

Explanation:

Step1: Analyze Parental Traits

Green pods (G) are dominant, yellow (g) is recessive. Let's assume: A (green, maybe GG or Gg), B (yellow, gg) since yellow is recessive (must be gg).

Step2: Analyze F1 Generation (C)

Cross A (green, say Gg if A is heterozygous, or GG) with B (gg). If A is GG: all C are Gg (green). If A is Gg: C has Gg (green) and gg (yellow)? Wait, no—wait, the problem says "a cross between a pea plant that has yellow pods (gg) and a pea plant that has green pods (G_: GG or Gg)". Green is dominant. So A is green (G_), B is yellow (gg).

Step3: Analyze F2 Generation (D and E)

C is the F1. If A is GG (homozygous dominant) and B is gg (homozygous recessive), then C (F1) is all Gg (green, since G is dominant). Then F2 (D and E) from C (Gg) self-cross: Gg x Gg. Offspring: GG (green), Gg (green), gg (yellow). So D (green) and E (maybe yellow or green). Wait, but let's re-examine the options. The correct logic: A is green (dominant parent), B is yellow (recessive parent). C is F1: since green is dominant, F1 (C) will be green (because even if A is Gg, Gg x gg would give Gg (green) and gg (yellow)? Wait, no—wait, the original cross is yellow (gg) and green (G_). If A is green (G_: could be GG or Gg). If A is GG: cross with B (gg) → all C (F1) are Gg (green). Then F2 (C self-cross: Gg x Gg) → offspring: GG (green), Gg (green), gg (yellow). So D (green) and E (maybe yellow). But the options include A, C, D. Wait, let's check the options:

Option 3: A, C, D only. Let's see: A is green (parent), B is yellow (parent). C is F1: since green is dominant, F1 (C) is green (because if A is GG, C is Gg; if A is Gg, C would be Gg (green) and gg (yellow)? No, wait, the flowchart: A and B are parents, C is F1, D and E are F2. So A (green parent), B (yellow parent). C (F1): if A is GG (homozygous green) and B is gg (homozygous yellow), then C is all Gg (green). Then F2 (C x C: Gg x Gg) → D (green, GG or Gg) and E (yellow, gg) or D (green) and E (green) or D (green) and E (yellow). Wait, but the key is dominant trait: green is dominant. So A (green parent) → green. C (F1) → since green is dominant, F1 will express green (even if heterozygous, Gg shows green). Then F2: when C (Gg) self-crosses, D (green, GG or Gg) and E (yellow, gg) or D (green) and E (green)? Wait, no—punnett square for Gg x Gg: 3/4 green (GG, Gg, Gg) and 1/4 yellow (gg). So D could be green, E could be yellow or green. But the options: A, C, D only. Let's check the options:

  • A: green parent (correct, since it's a green pod plant)
  • C: F1 (green, because dominant trait is expressed)
  • D: F2 (green, since 3/4 of F2 are green)
  • B: yellow (so not green)
  • E: maybe yellow (so not green)

So the correct squares are A, C, D only.

Answer:

A, C, and D only (the third option: "A, C, and D only")