4. a heterozygous tall, heterozygous green-flowered plant is crossed with a homozygous short, heterozygous…

4. a heterozygous tall, heterozygous green-flowered plant is crossed with a homozygous short, heterozygous green-flowered plant. what will be the possible genotypes and phenotypes of the offspring? show your work as a punnett square and write your answers as a phenotypic ratio.

4. a heterozygous tall, heterozygous green-flowered plant is crossed with a homozygous short, heterozygous green-flowered plant. what will be the possible genotypes and phenotypes of the offspring? show your work as a punnett square and write your answers as a phenotypic ratio.

Answer

Explanation:

Step1: Define parent genotypes

Let (T) = tall (dominant), (t) = short (recessive); (G) = green flower (dominant), (g) = non-green flower (recessive). Parent 1 (heterozygous tall, heterozygous green): (TtGg) Parent 2 (homozygous short, heterozygous green): (ttGg) Gametes of Parent 1: (TG, Tg, tG, tg) Gametes of Parent 2: (tG, tg, tG, tg)

Step2: Build correct Punnett Square

(TG) (Tg) (tG) (tg)
(tG) (TtGG) (TtGg) (ttGG) (ttGg)
(tg) (TtGg) (Ttgg) (ttGg) (ttgg)
(tG) (TtGG) (TtGg) (ttGG) (ttGg)
(tg) (TtGg) (Ttgg) (ttGg) (ttgg)

Step3: Classify phenotypes

  • Tall, green flower: (TtGG, TtGg) (count = 6)
  • Tall, non-green flower: (Ttgg) (count = 2)
  • Short, green flower: (ttGG, ttGg) (count = 6)
  • Short, non-green flower: (ttgg) (count = 2)

Step4: Simplify phenotypic ratio

Divide all counts by 2 to get the simplest whole-number ratio.

Answer:

Phenotypic ratio: 3 Tall, green-flowered : 1 Tall, non-green-flowered : 3 Short, green-flowered : 1 Short, non-green-flowered (or 3:1:3:1)