high population density can cause increases in competition for resources, such as food and shelter. the…

high population density can cause increases in competition for resources, such as food and shelter. the table shows the number of zebras living in four different regions.\n| |population of zebras|area (km²)| \n|--|--|--| \n|region a|1,312|212| \n|region b|630|314| \n|region c|16,400|625| \n|region d|17,800|902| \nin which region is competition for resources most likely the greatest?\n○ region a\n○ region b\n○ region c\n○ region d

high population density can cause increases in competition for resources, such as food and shelter. the table shows the number of zebras living in four different regions.\n| |population of zebras|area (km²)| \n|--|--|--| \n|region a|1,312|212| \n|region b|630|314| \n|region c|16,400|625| \n|region d|17,800|902| \nin which region is competition for resources most likely the greatest?\n○ region a\n○ region b\n○ region c\n○ region d

Answer

Answer:

C. Region C

Explanation:

Step1: Calculate population density for Region A

Population density = $\frac{1312}{212}\approx6.19$ zebras per $km^{2}$

Step2: Calculate population density for Region B

Population density = $\frac{630}{314}\approx2.01$ zebras per $km^{2}$

Step3: Calculate population density for Region C

Population density = $\frac{16400}{625}=26.24$ zebras per $km^{2}$

Step4: Calculate population density for Region D

Population density = $\frac{17800}{902}\approx19.73$ zebras per $km^{2}$

Step5: Compare densities

Since $26.24>19.73 > 6.19>2.01$, Region C has the highest population density and thus most competition for resources.