if the number of bacteria in a colony doubles every 475 hours and there is currently a population of 65…

if the number of bacteria in a colony doubles every 475 hours and there is currently a population of 65 bacteria, what will the population be 950 hours from now? bacteria

if the number of bacteria in a colony doubles every 475 hours and there is currently a population of 65 bacteria, what will the population be 950 hours from now? bacteria

Answer

Explanation:

Step1: Determine the number of doubling - periods

The bacteria doubles every 475 hours. The time elapsed is 950 hours. So, the number of doubling - periods $n=\frac{950}{475}$. $n = 2$

Step2: Calculate the final population

The initial population $P_0 = 65$. The formula for population growth is $P=P_0\times2^n$. Substitute $P_0 = 65$ and $n = 2$ into the formula. $P=65\times2^2$ $P=65\times4$ $P = 260$

Answer:

260