a parent that is heterozygous for a trait is crossed with a parent that is homozygous recessive for the same…

a parent that is heterozygous for a trait is crossed with a parent that is homozygous recessive for the same trait, as shown in the punnett square. what is the probability that the offspring will be homozygous dominant for this trait? 0% 25% 50% 75%

Answer

Explanation:

Step1: Identify the genotypes of the parents.

The problem states one parent is heterozygous (Tt) and the other is homozygous recessive (tt).

Step2: Determine the possible gametes for each parent.

The heterozygous parent (Tt) can produce gametes T and t. The homozygous recessive parent (tt) can only produce gamete t.

Step3: Construct the Punnett square.

Set up a Punnett square with the gametes from each parent along the top and side.

	T	t
t	Tt	tt
t	Tt	tt

Step4: Determine the genotypes of the offspring.

Fill in the squares by combining the gametes: The possible genotypes of the offspring are Tt and tt.

Step5: Calculate the probability of homozygous dominant offspring.

Homozygous dominant genotype is TT. Count the number of squares with the TT genotype. Number of TT offspring = 0 Total number of possible offspring = 4

Step6: Express the probability as a percentage.

The probability of homozygous dominant offspring (TT) is $\frac{0}{4} = 0$. $0 \times 100% = 0%$