parents that are heterozygous for having freckles (dominant) are crossed. which correctly describes their…

parents that are heterozygous for having freckles (dominant) are crossed. which correctly describes their offspring?\no twenty - five percent have freckles.\no twenty - five percent are ff.\no seventy - five percent have freckles.\no seventy - five percent are ff.

parents that are heterozygous for having freckles (dominant) are crossed. which correctly describes their offspring?\no twenty - five percent have freckles.\no twenty - five percent are ff.\no seventy - five percent have freckles.\no seventy - five percent are ff.

Answer

Explanation:

Step1: Set up the cross

Let F represent the dominant allele for freckles and f represent the recessive allele. Heterozygous parents have the genotype Ff. The cross is Ff x Ff.

Step2: Create a Punnett - square

The possible gametes from each parent are F and f. The Punnett - square has 4 boxes. The combinations are FF, Ff, Ff, and ff.

Step3: Analyze genotypes and phenotypes

FF and Ff genotypes result in the freckled phenotype (dominant). ff results in no freckles (recessive). Out of 4 possible genotypes, 3 (FF, Ff, Ff) result in freckles. So the proportion of offspring with freckles is $\frac{3}{4}= 75%$.

Answer:

Seventy - five percent have freckles.