part 1: fill in the basic conversions based on what you learned this week.\n1. 1 ft = 12 in\n2. 1 yd = 3…

part 1: fill in the basic conversions based on what you learned this week.\n1. 1 ft = 12 in\n2. 1 yd = 3 ft\n3. 1 in = 2.54 cm\n4. 1 lb. = 16 oz\n5. 1 kg = 2.2 lb\n6. 1 kg = 1000 g\npart 2: now, apply what you learned to figure out the following conversions.\n7. 4 ft = 48 in\n8. 5 ft = 60 in\n9. 67 in = 5 ft 7 in\n10. 54 in = 4 ft 6 in\n11. 12 ft = 4 yd\n12. 6 in = 15.24 cm\n13. 25.4 cm =\n14. 4 lb = 64 oz\n15. 32 oz = 2 lb\n16. 7 kg =\n17. 55 lb =\n18. 121 lb =\n19. 3.5 kg =\n20. 4000 g =\nbonus:\ndr. kolatis prefers to place her sutures 2 cm apart. she has a patient who comes into the er with a large laceration measuring 8 in long. approximately how many sutures will she need to place?

part 1: fill in the basic conversions based on what you learned this week.\n1. 1 ft = 12 in\n2. 1 yd = 3 ft\n3. 1 in = 2.54 cm\n4. 1 lb. = 16 oz\n5. 1 kg = 2.2 lb\n6. 1 kg = 1000 g\npart 2: now, apply what you learned to figure out the following conversions.\n7. 4 ft = 48 in\n8. 5 ft = 60 in\n9. 67 in = 5 ft 7 in\n10. 54 in = 4 ft 6 in\n11. 12 ft = 4 yd\n12. 6 in = 15.24 cm\n13. 25.4 cm =\n14. 4 lb = 64 oz\n15. 32 oz = 2 lb\n16. 7 kg =\n17. 55 lb =\n18. 121 lb =\n19. 3.5 kg =\n20. 4000 g =\nbonus:\ndr. kolatis prefers to place her sutures 2 cm apart. she has a patient who comes into the er with a large laceration measuring 8 in long. approximately how many sutures will she need to place?

Answer

Explanation:

Step1: Convert 8 inches to centimeters

Since 1 in = 2.54 cm, then for 8 inches, we have $8\times2.54 = 20.32$ cm.

Step2: Calculate the number of sutures

The sutures are placed 2 cm apart. So the number of sutures $n=\frac{20.32}{2}\approx10$ (we round up because we need to cover the entire length).

Answer:

10

For the remaining blanks in Part 2: 16. Since 1 kg = 2.2 lb, then 7 kg = $7\times2.2=15.4$ lb. 17. Since 1 kg = 2.2 lb, then 55 lb = $\frac{55}{2.2}=25$ kg. 18. Since 1 kg = 2.2 lb, then 121 lb = $\frac{121}{2.2}=55$ kg. 19. Since 1 kg = 1000 g, then 3.5 kg = $3.5\times1000 = 3500$ g. 20. Since 1 kg = 1000 g, then 4000 g = $\frac{4000}{1000}=4$ kg. 13. Since 1 in = 2.54 cm, then 25.4 cm = $\frac{25.4}{2.54}=10$ in.