a pea plant that has round seeds has the genotype rr. it is crossed with a pea plant that has wrinkled seeds…
a pea plant that has round seeds has the genotype rr. it is crossed with a pea plant that has wrinkled seeds and the genotype rr. what is the probability that the offspring will have wrinkled seeds?\n0 percent\n25 percent\n50 percent\n75 percent
Answer
Explanation:
Step1: Set up the Punnett - square
The genotypes of the parents are Rr and rr. The possible gametes from the Rr parent are R and r, and the possible gametes from the rr parent are r and r.
Step2: Fill in the Punnett - square
| R | r | |
|---|---|---|
| r | Rr | rr |
| r | Rr | rr |
Step3: Calculate the probability
Out of the 4 possible genotypes of the offspring (2 Rr and 2 rr), 2 are rr. The probability of getting an rr (wrinkled - seed) genotype is $\frac{2}{4}=0.5$ or 50%.
Answer:
50 percent