a pea plant that has round seeds has the genotype rr. it is crossed with a pea plant that has wrinkled seeds…
a pea plant that has round seeds has the genotype rr. it is crossed with a pea plant that has wrinkled seeds and the genotype rr. what is the probability that the offspring will have wrinkled seeds? 0 percent 25 percent 50 percent 75 percent
Answer
Explanation:
Step1: Set up the Punnett - square
The genotypes of the parents are Rr and rr. The possible gametes from the Rr parent are R and r, and the possible gametes from the rr parent are r and r.
Step2: Fill in the Punnett - square
| R | r | |
|---|---|---|
| r | Rr | rr |
| r | Rr | rr |
Step3: Calculate the probability
Out of the 4 possible genotypes of the offspring (2 Rr and 2 rr), 2 are rr (wrinkled - seed genotype). The probability is $\frac{2}{4}=0.5$ or 50%.
Answer:
50 percent