in pea plants, the allele for tall plants (t) is dominant over the allele for short plants (t). the allele…

in pea plants, the allele for tall plants (t) is dominant over the allele for short plants (t). the allele for purple flowers (p) is dominant over the allele for white flowers (p). two plants that are heterozygous for both traits are crossed, as shown in the punnett square. what is the phenotypic ratio you would expect to see in the offspring? a. 9 tall purple : 3 tall white : 3 short purple : 1 short white b. 3 tall purple : 1 short white c. 2 tall white : 2 short purple d. 1 tall purple : 3 short white
Answer
Answer:
A. 9 tall purple : 3 tall white : 3 short purple : 1 short white
Explanation:
Step1: Analyze tall - short trait
For the height trait (T/t), (T) (tall) is dominant over (t) (short). The cross of (Tt\times Tt) gives a phenotypic ratio of (3) tall ((TT + Tt)) : (1) short ((tt)).
Step2: Analyze purple - white trait
For the flower color trait (P/p), (P) (purple) is dominant over (p) (white). The cross of (Pp\times Pp) gives a phenotypic ratio of (3) purple ((PP+Pp)) : (1) white ((pp)).
Step3: Use the multiplication rule (for independent traits)
The combined phenotypic ratio for two independent traits (height and flower color) is ((3) tall : (1) short()\times(3) purple : (1) white()). [ \begin{align*} &(3T -:1tt)\times(3P -:1pp)\ =&3T-\times3P -:3T-\times1pp:1tt\times3P -:1tt\times1pp\ =&9T - P -:3T - pp:3ttP -:1ttpp \end{align*} ] So the phenotypic ratio is (9) tall purple : (3) tall white : (3) short purple : (1) short white.