in a population of rabbits, the frequency of q is 0.37. what is the frequency of p?\n0.37\n0.50\n0.63\n0.86
in a population of rabbits, the frequency of q is 0.37. what is the frequency of p?\n0.37\n0.50\n0.63\n0.86
Answer
Answer:
C. 0.63
Explanation:
Step1: Use the Hardy - Weinberg equation
In the Hardy - Weinberg equilibrium, (p + q=1), where (p) is the frequency of one allele and (q) is the frequency of the other allele.
Step2: Solve for (p)
Given (q = 0.37), we substitute into the equation (p=1 - q). So (p=1 - 0.37=\frac{100}{100}-\frac{37}{100}=\frac{100 - 37}{100}=\frac{63}{100}=0.63)