what is the probability of the offspring having hemophilia for the cross that is shown in the punnett…

Explanation:

Step1: Analyze Punnett - square

A Punnett - square shows the possible genotypes of offspring from a genetic cross. In the case of hemophilia, which is an X - linked recessive disorder. Let (X^h) represent the allele for hemophilia.

Step2: Count genotypes

Assume the cross is between parents with genotypes such that the Punnett - square is set up. If we count the total number of genotypes in the Punnett - square (4 in this case) and the number of genotypes that result in hemophilia. Since hemophilia is X - linked recessive, a male with (X^hY) and a female with (X^hX^h) would have the disorder. Looking at the Punnett - square, if we assume the cross is set up correctly, and we see that 1 out of 4 genotypes is for an affected individual.

Step3: Calculate probability

The probability (P) of an event is given by the formula (P=\frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}). Here, the number of favorable outcomes (offspring with hemophilia) is 1 and the total number of outcomes is 4. So (P = \frac{1}{4}=0.25) or 25%.

Answer:

25 percent