what is the probability of the offspring having hemophilia for the cross that is shown in the punnett…

Explanation:

Step1: Understand hemophilia inheritance

Hemophilia is an X - linked recessive disorder. Let $X^H$ be the normal allele and $X^h$ be the hemophilia - causing allele. Males have XY chromosomes and females have XX chromosomes. A male with $X^hY$ has hemophilia, and a female needs to be $X^hX^h$ to have hemophilia.

Step2: Analyze the Punnett - square genotypes

The possible genotypes from the cross in the Punnett - square are $X^HX^h$, $X^HY$, $X^hX^h$, $X^hY$.

Step3: Count the number of affected genotypes

Out of the 4 possible genotypes, 1 is $X^hY$ (affected male) and 1 is $X^hX^h$ (affected female). So, there are 2 affected genotypes out of 4.

Step4: Calculate the probability

The probability $P=\frac{\text{Number of affected genotypes}}{\text{Total number of genotypes}}=\frac{2}{4} = 0.5$ or 50%.

Answer:

50 percent