the punnett square shows the cross for a particular trait between a homozygous dominant parent and a…

the punnett square shows the cross for a particular trait between a homozygous dominant parent and a heterozygous parent. what is the probability the offspring will be heterozygous for this trait? 25% 50% 75% 100%

the punnett square shows the cross for a particular trait between a homozygous dominant parent and a heterozygous parent. what is the probability the offspring will be heterozygous for this trait? 25% 50% 75% 100%

Answer

Explanation:

Step1: Fill the Punnett - square

The homozygous dominant parent has genotype AA and the heterozygous parent has genotype Aa. When we fill the Punnett - square: The top row has alleles A and A (from the homozygous dominant parent), and the left - hand column has alleles A and a (from the heterozygous parent). The four boxes in the Punnett - square will have genotypes: AA, AA, Aa, Aa.

Step2: Calculate the probability

There are 4 possible genotypes for the offspring. Out of these 4, 2 are heterozygous (Aa). The probability of an event is calculated as $\frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}$. The number of favorable outcomes (heterozygous offspring) is 2, and the total number of outcomes is 4. The probability $P=\frac{2}{4}=0.5$ or 50%.

Answer:

50%