the punnett square shows the possible genotype combinations of two parents who are homozygous for a trait…

the punnett square shows the possible genotype combinations of two parents who are homozygous for a trait. what is the probability of the parents having a child that is heterozygous for this trait? 0% 25% 75% 100%

the punnett square shows the possible genotype combinations of two parents who are homozygous for a trait. what is the probability of the parents having a child that is heterozygous for this trait? 0% 25% 75% 100%

Answer

Explanation:

Step1: Count total genotypes

There are 4 boxes in the Punnett - square, so the total number of possible genotypes is 4.

Step2: Count heterozygous genotypes

All 4 genotypes in the Punnett - square are Ww (heterozygous).

Step3: Calculate probability

The probability $P$ of an event is given by the formula $P=\frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}$. Here, the number of favorable outcomes (heterozygous genotypes) is 4, and the total number of outcomes is 4. So $P = \frac{4}{4}=1 = 100%$.

Answer:

100%