question 6\nfind the value of $2^{-2}cdotsqrt3{8^{2}}$\n\nquestion 7\nfind the product of $(2.6\times…

question 6\nfind the value of $2^{-2}cdotsqrt3{8^{2}}$\n\nquestion 7\nfind the product of $(2.6\times 10^{-4})(4.5\times 10^{8})$\n\nthe diameter of a red blood cell is about 50 times the diameter of a white b\nthe diameter of a red blood cell is about 2 times the diameter of a white blo\nthe diameter of a red blood cell is about 20 times the diameter of a white blc\nthe diameter of a red blood cell is about 5 times the diameter of a white bloc

question 6\nfind the value of $2^{-2}cdotsqrt3{8^{2}}$\n\nquestion 7\nfind the product of $(2.6\times 10^{-4})(4.5\times 10^{8})$\n\nthe diameter of a red blood cell is about 50 times the diameter of a white b\nthe diameter of a red blood cell is about 2 times the diameter of a white blo\nthe diameter of a red blood cell is about 20 times the diameter of a white blc\nthe diameter of a red blood cell is about 5 times the diameter of a white bloc

Answer

Answer:

Question 6

$\frac{1}{2}$

Question 7

$1.17\times 10^{5}$

Explanation:

Question 6

Step1: Simplify each part

$2^{-2}=\frac{1}{2^{2}}=\frac{1}{4}$, $\sqrt[3]{8^{2}}=\sqrt[3]{(2^{3})^{2}} = 2^{2}=4$

Step2: Calculate the product

$2^{-2}\cdot\sqrt[3]{8^{2}}=\frac{1}{4}\times4 = 1$

Question 7

Step1: Multiply the coefficients

$2.6\times4.5 = 11.7$

Step2: Add the exponents of 10

$10^{-4}\times10^{8}=10^{-4 + 8}=10^{4}$

Step3: Write in scientific - notation

$11.7\times10^{4}=1.17\times10^{5}$