a scientist is studying fruit fly wings. straight wings are dominant, and curly wings are recessive. which…
a scientist is studying fruit fly wings. straight wings are dominant, and curly wings are recessive. which statement correctly describes the f₁ generation if a straight - winged parent is crossed with a curly - winged parent and if both parents are true breeding?\nthe offspring will have two genes for straight wings.\nthe offspring will produce only gametes that have genes for curly wings.\nthe offspring will have one allele for straight wings and one allele for curly wings.\nthe offspring will have only one kind of allele for the gene that determines wing type.
Answer
Brief Explanations:
Let's assume the allele for straight wings is (S) (dominant) and for curly wings is (s) (recessive). The straight - winged parent (true - breeding) has a genotype (SS), and the curly - winged parent has a genotype (ss). When they are crossed ((SS\times ss)):
- For the first option: Offspring will not have two genes ((SS)) for straight wings. The cross (SS\times ss) gives (Ss) offspring.
- For the second option: Offspring ((Ss)) will not produce only gametes with (s) (curly - winged genes). They will produce gametes with (S) and (s) in equal proportion.
- For the third option: Using the cross (SS\times ss), by the law of segregation, the offspring will get one allele ((S)) from the straight - winged parent and one allele ((s)) from the curly - winged parent. So the genotype of the offspring is (Ss).
- For the fourth option: Offspring ((Ss)) have two different alleles ((S) and (s)) for the wing - type gene, not only one kind of allele.
Answer:
The offspring will have one allele for straight wings and one allele for curly wings.