two fruit flies that are heterozygous for body color and eye color are crossed. brown body color is dominant…

two fruit flies that are heterozygous for body color and eye color are crossed. brown body color is dominant to black body color. red eye color is dominant to brown eye color. use the punnett square to determine the ratio of offspring with the described trait to the total number of offspring: brown body and red eyes brown body and brown eyes black body and red eyes black body and brown eyes done

two fruit flies that are heterozygous for body color and eye color are crossed. brown body color is dominant to black body color. red eye color is dominant to brown eye color. use the punnett square to determine the ratio of offspring with the described trait to the total number of offspring: brown body and red eyes brown body and brown eyes black body and red eyes black body and brown eyes done

Answer

Explanation:

Step1: Count brown - body and red - eyes offspring

Count the genotypes with at least one B (for brown body) and at least one E (for red eyes). There are 9 such genotypes: BBEE, BBEe, BbEE, BbEe (counted multiple times as they appear in the square). So the ratio is $\frac{9}{16}$.

Step2: Count brown - body and brown - eyes offspring

Count the genotypes with at least one B and two ee. There are 3 such genotypes: BBee, Bbee. So the ratio is $\frac{3}{16}$.

Step3: Count black - body and red - eyes offspring

Count the genotypes with bb and at least one E. There are 3 such genotypes: bbEE, bbEe. So the ratio is $\frac{3}{16}$.

Step4: Count black - body and brown - eyes offspring

Count the genotype with bb and ee. There is 1 such genotype: bbee. So the ratio is $\frac{1}{16}$.

Answer:

Brown body and red eyes: $\frac{9}{16}$ Brown body and brown eyes: $\frac{3}{16}$ Black body and red eyes: $\frac{3}{16}$ Black body and brown eyes: $\frac{1}{16}$