an accountant assigns double - digit codes to four different clients—frank, gardner, hunt and jordan. the…

an accountant assigns double - digit codes to four different clients—frank, gardner, hunt and jordan. the codes are made using the digits 1 through 8, and the accountant uses each digit only once. the following conditions must apply: the code with a six in the tens place has a three in the units place. hunts code has a higher numeric value than jordans code does. franks code has the highest numeric value. jordans code ends with a two. three of the four codes are even. 3. if gardners code has a lower numeric value than jordans code, which one of the following must be false? (a) gardners code ends with a 4. (b) gardners code ends with a 3. (c) gardners code ends with an 8. (d) franks code ends with a 4. (e) franks code ends with an 8.

an accountant assigns double - digit codes to four different clients—frank, gardner, hunt and jordan. the codes are made using the digits 1 through 8, and the accountant uses each digit only once. the following conditions must apply: the code with a six in the tens place has a three in the units place. hunts code has a higher numeric value than jordans code does. franks code has the highest numeric value. jordans code ends with a two. three of the four codes are even. 3. if gardners code has a lower numeric value than jordans code, which one of the following must be false? (a) gardners code ends with a 4. (b) gardners code ends with a 3. (c) gardners code ends with an 8. (d) franks code ends with a 4. (e) franks code ends with an 8.

Answer

Explanation:

Step1: Analyze given information

We know digits 1 - 8 are used once for double - digit codes for 4 clients. Code with 6 in tens has 3 in units. Hunt > Jordan, Frank is highest. Jordan ends with 2. 3 out of 4 codes are even. Also, Gardner < Jordan.

Step2: Determine possible order

Since Frank is highest, Hunt > Jordan and Gardner < Jordan, the order from highest to lowest is Frank > Hunt > Jordan > Gardner.

Step3: Consider digit properties

Jordan ends with 2. Since 3 out of 4 codes are even, and the code with 6 in tens has 3 in units (odd), the other three codes must be even.

Step4: Evaluate options

If Gardner < Jordan and Jordan ends with 2, Gardner's code cannot end with 3 (because codes are double - digit and using digits 1 - 8 once, and 3 is already used in the 63 code and Gardner's code is lower value and needs to be even as 3 out of 4 codes are even).

Answer:

B. Gardner's code ends with a 3.