city\tcost (rs)\nsalvador\t224\nduque de caxias\t242\nrio de janeiro\t193\ncampinas\t185\nporto…

city\tcost (rs)\nsalvador\t224\nduque de caxias\t242\nrio de janeiro\t193\ncampinas\t185\nporto alegre\t153\nguarulhos\t120\nfortaleza\t201\nhenrys original plan was to visit duque de caxias, campinas, rio de janeiro, and guarulhos. however, he only has r$699 to spend, so he cannot afford to use his original itinerary. which of the following changes will be the cheapest swap henry can make and still come in under budget?\na. replace duque de caxias with salvador.\nb. replace duque de caxias with fortaleza.\nc. replace rio de janeiro with porto alegre.\nd. do not visit guarulhos.

city\tcost (rs)\nsalvador\t224\nduque de caxias\t242\nrio de janeiro\t193\ncampinas\t185\nporto alegre\t153\nguarulhos\t120\nfortaleza\t201\nhenrys original plan was to visit duque de caxias, campinas, rio de janeiro, and guarulhos. however, he only has r$699 to spend, so he cannot afford to use his original itinerary. which of the following changes will be the cheapest swap henry can make and still come in under budget?\na. replace duque de caxias with salvador.\nb. replace duque de caxias with fortaleza.\nc. replace rio de janeiro with porto alegre.\nd. do not visit guarulhos.

Answer

Answer:

c. Replace Rio de Janeiro with Porto Alegre.

Explanation:

Step1: Calculate original cost

Original cities: Duque de Caxias (242), Campinas (185), Rio de Janeiro (193), Guarulhos (120). Original cost = 242 + 185+193 + 120=740.

Step2: Analyze option a

Replace Duque de Caxias (242) with Salvador (224). New cost = 224+185 + 193+120 = 722.

Step3: Analyze option b

Replace Duque de Caxias (242) with Fortaleza (201). New cost = 201+185 + 193+120 = 699.

Step4: Analyze option c

Replace Rio de Janeiro (193) with Porto Alegre (153). New cost = 242+185 + 153+120 = 700.

Step5: Analyze option d

Do not visit Guarulhos (120). New cost = 242+185 + 193=620.

Step6: Compare costs

Option a cost: 722, Option b cost: 699, Option c cost: 700, Option d cost: 620. But we are looking for the cheapest swap. Option b involves replacing one city, and option d involves removing a city. Among the swap - only options (a, b, c), option c has the lowest cost increase among the swap - based changes.