ron charges $10 to park a car in his parking lot. he pays $50 per day to rent the lot. if 40 cars park in…

ron charges $10 to park a car in his parking lot. he pays $50 per day to rent the lot. if 40 cars park in his lot during the day, how much does he earn after expenses? choose the correct solution to this problem. f(x)=10x - 50 f(40)=10(40)-50 f(40)=400 - 50 f(40)=350 he earns $350. f(x)=10x - 50 f(40)=10(40)-50 f(40)=400 - 50 f(40)=350 f(40)-40=350 - 40 f = 310 he earns $310. f(x)-50 = 10x f(40)-50 = 10(40) f(40)-50 = 400 f(40)-50 + 50 = 400+50 f(40)=450 he earns $450. f(x)=10x - 50 f(40)=10(40)-50 f(40)=400 - 50 f(40)=350 f(40)/40 = 350/40 f = 87.5

ron charges $10 to park a car in his parking lot. he pays $50 per day to rent the lot. if 40 cars park in his lot during the day, how much does he earn after expenses? choose the correct solution to this problem. f(x)=10x - 50 f(40)=10(40)-50 f(40)=400 - 50 f(40)=350 he earns $350. f(x)=10x - 50 f(40)=10(40)-50 f(40)=400 - 50 f(40)=350 f(40)-40=350 - 40 f = 310 he earns $310. f(x)-50 = 10x f(40)-50 = 10(40) f(40)-50 = 400 f(40)-50 + 50 = 400+50 f(40)=450 he earns $450. f(x)=10x - 50 f(40)=10(40)-50 f(40)=400 - 50 f(40)=350 f(40)/40 = 350/40 f = 87.5

Answer

Explanation:

Step1: Define the profit - function

The revenue from parking $x$ cars is $10x$ (since he charges $10$ per car), and the cost of renting the lot is $50$ per day. So the profit function $f(x)=10x - 50$.

Step2: Substitute the number of cars

We know that $x = 40$ (the number of cars that parked in the lot). Substitute $x = 40$ into the function: $f(40)=10\times40-50$.

Step3: Calculate the result

First, calculate $10\times40 = 400$, then $400-50=350$.

Answer:

He earns $350$. So the correct solution is the one that says $f(x)=10x - 50$, $f(40)=10(40)-50$, $f(40)=400 - 50$, $f(40)=350$. He earns $350$.