select the correct answer from the drop - down menu. the table shows the results from a survey of 335…

select the correct answer from the drop - down menu. the table shows the results from a survey of 335 randomly selected households with pets. this survey was conducted by a new pet store that is opening nearby. \n| | have children | do not have children | total |\n|----|----|----|----|\n| 1 pet | 38 | 53 | 91 |\n| 2 pets | 85 | 41 | 126 |\n| 3 or more pets | 46 | 72 | 118 |\n| total | 169 | 166 | 335 |\nthe pet store uses the data to make decisions about inventory. complete the given statement. a customer is more likely to have 1 pet and no children than they are to have

select the correct answer from the drop - down menu. the table shows the results from a survey of 335 randomly selected households with pets. this survey was conducted by a new pet store that is opening nearby. \n| | have children | do not have children | total |\n|----|----|----|----|\n| 1 pet | 38 | 53 | 91 |\n| 2 pets | 85 | 41 | 126 |\n| 3 or more pets | 46 | 72 | 118 |\n| total | 169 | 166 | 335 |\nthe pet store uses the data to make decisions about inventory. complete the given statement. a customer is more likely to have 1 pet and no children than they are to have

Answer

Explanation:

Step1: Calculate probability of 1 pet and no children

The number of customers with 1 pet and no children is 53. The total number of customers is 335. So the probability $P(1\text{ pet}, \text{no children})=\frac{53}{335}$.

Step2: Calculate probability of 3 pets and children

The number of customers with 3 or more pets and children is 46. The probability $P(3\text{ pets}, \text{children})=\frac{46}{335}$.

Step3: Calculate probability of 2 pets and children

The number of customers with 2 pets and children is 85. The probability $P(2\text{ pets}, \text{children})=\frac{85}{335}$.

Step4: Calculate probability of 3 pets and no children

The number of customers with 3 or more pets and no children is 72. The probability $P(3\text{ pets}, \text{no children})=\frac{72}{335}$.

Step5: Compare probabilities

Since $\frac{53}{335}<\frac{85}{335}$, $\frac{53}{335}<\frac{72}{335}$ and $\frac{53}{335}>\frac{46}{335}$.

Answer:

3 pets and children