14. -/1 points details my notes scalc9 3.1.029. find the critical numbers of the function. (enter your…
14. -/1 points details my notes scalc9 3.1.029. find the critical numbers of the function. (enter your answers as a comma - separated list. if an answer does not exist, enter dne.) f(x)=8x^2 + x - 3 x = need help? read it submit answer 15. -/1 points details my notes scalc9 3.1.030.
Answer
Explanation:
Step1: Find the derivative
The derivative of $f(x)=8x^{2}+x - 3$ using the power - rule $(x^n)'=nx^{n - 1}$ is $f'(x)=16x + 1$.
Step2: Set the derivative equal to zero
Set $f'(x)=0$, so $16x+1 = 0$.
Step3: Solve for x
Subtract 1 from both sides: $16x=-1$. Then divide by 16, we get $x=-\frac{1}{16}$.
Answer:
$-\frac{1}{16}$