f(x) = (-x + 1)/(x^2 - 16)\nptotes, if any, on the graph.\nelected, that number of lines are available to…

f(x) = (-x + 1)/(x^2 - 16)\nptotes, if any, on the graph.\nelected, that number of lines are available to plot. select a location on the grid to plot a li\nenable zo

f(x) = (-x + 1)/(x^2 - 16)\nptotes, if any, on the graph.\nelected, that number of lines are available to plot. select a location on the grid to plot a li\nenable zo

Answer

Explanation:

Step1: Find vertical asymptotes

Set the denominator equal to 0. So, $x^{2}-16 = 0$. Factoring, we get $(x + 4)(x - 4)=0$. Solving for $x$, we have $x=-4$ and $x = 4$.

Step2: Find horizontal asymptote

Degree of numerator is 1 and degree of denominator is 2. When degree of denominator is greater than degree of numerator, the horizontal - asymptote is $y = 0$.

Answer:

Vertical asymptotes: $x=-4,x = 4$; Horizontal asymptote: $y = 0$