4. f(x) = (x - 2)/(2x + 1) find the horizontal asymptote. none y = 0 y = 1/2 y = -2

4. f(x) = (x - 2)/(2x + 1) find the horizontal asymptote. none y = 0 y = 1/2 y = -2

4. f(x) = (x - 2)/(2x + 1) find the horizontal asymptote. none y = 0 y = 1/2 y = -2

Answer

Explanation:

Step1: Identify degree of polynomials

The degree of the numerator $n = 1$ (for $x - 2$) and the degree of the denominator $m=1$ (for $2x + 1$).

Step2: Use horizontal - asymptote rule

When $n = m$, the horizontal asymptote is $y=\frac{a_n}{b_m}$, where $a_n$ is the leading coefficient of the numerator and $b_m$ is the leading coefficient of the denominator. Here, $a_n = 1$ and $b_m=2$. So $y=\frac{1}{2}$.

Answer:

C. $y=\frac{1}{2}$