according to the table, which ordered pair is a local maximum of the function, f(x)?\n-2 0\n-1 45\n0 64\n1…

according to the table, which ordered pair is a local maximum of the function, f(x)?\n-2 0\n-1 45\n0 64\n1 45\n2 0\n3 -35\n4 0\n5 189\n6 640\n(0, 64)\n(3, -35)\n(5, 189)\n(2, 0)

according to the table, which ordered pair is a local maximum of the function, f(x)?\n-2 0\n-1 45\n0 64\n1 45\n2 0\n3 -35\n4 0\n5 189\n6 640\n(0, 64)\n(3, -35)\n(5, 189)\n(2, 0)

Answer

Explanation:

Step1: Understand local maximum

A local maximum is a point where the function value is greater than the values at neighboring points.

Step2: Analyze the table

We check the $f(x)$ - values around each $x$ - value. At $x = 0$, $f(-1)=45$, $f(0) = 64$, $f(1)=45$. The value of $f(x)$ at $x = 0$ is greater than its neighboring $f(x)$ - values.

Answer:

(0, 64)