add the fractional parts. what is \\(\\frac{1}{2} + \\left(-\\frac{1}{2}\\right)\\)?\n\\(1\\frac{1}{2} +…

add the fractional parts. what is \\(\\frac{1}{2} + \\left(-\\frac{1}{2}\\right)\\)?\n\\(1\\frac{1}{2} + \\left(-2\\frac{1}{2}\\right) = 1 + \\frac{1}{2} + \\left(-2\\frac{1}{2}\\right)\\)\n\\(= 1 + \\frac{1}{2} + (-2) + \\left(-\\frac{1}{2}\\right)\\)\n\\(= 1 + (-2) + \\frac{1}{2} + \\left(-\\frac{1}{2}\\right)\\)\n\\(= -1 + \\frac{1}{2} + \\left(-\\frac{1}{2}\\right)\\)\n\\(= -1 + \\square\\)

add the fractional parts. what is \\(\\frac{1}{2} + \\left(-\\frac{1}{2}\\right)\\)?\n\\(1\\frac{1}{2} + \\left(-2\\frac{1}{2}\\right) = 1 + \\frac{1}{2} + \\left(-2\\frac{1}{2}\\right)\\)\n\\(= 1 + \\frac{1}{2} + (-2) + \\left(-\\frac{1}{2}\\right)\\)\n\\(= 1 + (-2) + \\frac{1}{2} + \\left(-\\frac{1}{2}\\right)\\)\n\\(= -1 + \\frac{1}{2} + \\left(-\\frac{1}{2}\\right)\\)\n\\(= -1 + \\square\\)

Answer

Explanation:

Step1: Identify the fractional parts to add

We need to find the sum of $\frac{1}{2}$ and $-\frac{1}{2}$.

Step2: Add the fractions

Using the rule for adding a number and its opposite (additive inverses), $\frac{1}{2} + \left(-\frac{1}{2}\right) = 0$. So the value to fill in the square is the result of $\frac{1}{2} + \left(-\frac{1}{2}\right)$, which is $0$.

Answer:

$0$