alejandra correctly wrote the equation $y - 3 = \\frac{1}{5}(x - 10)$ to represent a line that her teacher…

alejandra correctly wrote the equation $y - 3 = \\frac{1}{5}(x - 10)$ to represent a line that her teacher sketched. the teacher then changed the line so it had a slope of 2, but still went through the same point. which equation should alejandra write to represent the new line?\\n\\(\\circ\\) $y - 6 = 2(x - 10)$\\n\\(\\circ\\) $y - 2 = \\frac{1}{5}(x - 10)$\\n\\(\\circ\\) $y - 3 = \\frac{1}{5}(x - 2)$\\n\\(\\circ\\) $y - 3 = 2(x - 10)$
Answer
Explanation:
Step1: Recall Point - Slope Form
The point - slope form of a linear equation is $y - y_1=m(x - x_1)$, where $(x_1,y_1)$ is a point on the line and $m$ is the slope of the line.
Step2: Identify the Point and New Slope
From the original equation $y - 3=\frac{1}{5}(x - 10)$, we can see that the line passes through the point $(x_1,y_1)=(10,3)$ and has a slope $m = \frac{1}{5}$. The new line has the same point $(10,3)$ (since it still goes through the same point) and a new slope $m = 2$.
Step3: Substitute into Point - Slope Form
Using the point - slope form $y - y_1=m(x - x_1)$ with $x_1 = 10$, $y_1=3$ and $m = 2$, we get $y - 3=2(x - 10)$.
Answer:
$y - 3 = 2(x - 10)$ (the fourth option: $y - 3 = 2(x - 10)$)