$y = -(3)^{x+5}$\nwhat is the asymptote?\n$x = 5$\n$x = -5$\n$y = 0$\n$y = -5$

Explanation:

Step1: Recall exponential function asymptote

For a basic exponential function $y = b^x$ (where $b>0, b\neq1$), the horizontal asymptote is $y=0$, as $\lim_{x\to-\infty} b^x = 0$.

Step2: Analyze transformed function

The given function is $y = -3^{x+5}$. This is a transformation of $y=3^x$: shifted left 5 units and reflected over the x-axis. The limit $\lim_{x\to-\infty} -3^{x+5} = -0 = 0$.

Step3: Identify the asymptote

The horizontal asymptote remains $y=0$ because the vertical shift and reflection do not change the end behavior as $x$ approaches negative infinity.

Answer:

C. y = 0