average rate of change practice\ncomplete this assessment to review what youve learned. it will not count…

average rate of change practice\ncomplete this assessment to review what youve learned. it will not count toward your grade\nuse the image to answer the question\ndescribe the behavior of the function by determining over which interval the function has a negative average rate of change. consider only intervals with consecutive endpoints shown on the graph.\n(1 point)\nthe average rate of change is negative over the interval
Answer
Explanation:
Step1: Recall average - rate - of - change formula
The average rate of change of a function $y = f(x)$ over the interval $[a,b]$ is $\frac{f(b)-f(a)}{b - a}$. If $\frac{f(b)-f(a)}{b - a}<0$, then $f(b)-f(a)$ and $b - a$ have opposite signs. Since $b>a$ (for an interval $[a,b]$), we need $f(b)<f(a)$.
Step2: Analyze intervals on the graph
- For the interval $[0,1]$: $f(0) = 0$, $f(1)=4$, and $\frac{f(1)-f(0)}{1 - 0}=\frac{4 - 0}{1}=4>0$.
- For the interval $[1,2]$: $f(1)=4$, $f(2)=4$, and $\frac{f(2)-f(1)}{2 - 1}=\frac{4 - 4}{1}=0$.
- For the interval $[2,3]$: $f(2)=4$, $f(3)=0$, and $\frac{f(3)-f(2)}{3 - 2}=\frac{0 - 4}{1}=- 4<0$.
- For the interval $[3,4]$: $f(3)=0$, $f(4)=4$, and $\frac{f(4)-f(3)}{4 - 3}=\frac{4 - 0}{1}=4>0$.
- For the interval $[4,5]$: $f(4)=4$, $f(5)=4$, and $\frac{f(5)-f(4)}{5 - 4}=\frac{4 - 4}{1}=0$.
Answer:
$[2,3]$