average rate of change quick check\nuse the image to answer the question.\ndescribe the graph of f(x) by…

average rate of change quick check\nuse the image to answer the question.\ndescribe the graph of f(x) by selecting the correct statement.\n(1 point)\nthe average rate of change is negative on the interval 1,3 and also on the interval 6,7.\nthe average rate of change is negative only on the interval 1,3.\nthe average rate of change is negative only on the interval 6,7.\nthe average rate of change is negative on the interval 0,1 and on the interval 3,4

average rate of change quick check\nuse the image to answer the question.\ndescribe the graph of f(x) by selecting the correct statement.\n(1 point)\nthe average rate of change is negative on the interval 1,3 and also on the interval 6,7.\nthe average rate of change is negative only on the interval 1,3.\nthe average rate of change is negative only on the interval 6,7.\nthe average rate of change is negative on the interval 0,1 and on the interval 3,4

Answer

Explanation:

Step1: Recall average - rate - of - change formula

The average rate of change of a function $y = f(x)$ over the interval $[a,b]$ is given by $\frac{f(b)-f(a)}{b - a}$. If $f(b)-f(a)<0$ and $b - a>0$ (since $b>a$ for an interval $[a,b]$), the average rate of change is negative.

Step2: Analyze interval $[1,3]$

For the interval $[1,3]$, $f(1) = 1$ and $f(3)=0$. Then $\frac{f(3)-f(1)}{3 - 1}=\frac{0 - 1}{2}=-\frac{1}{2}<0$.

Step3: Analyze interval $[6,7]$

For the interval $[6,7]$, $f(6) = 2$ and $f(7)=0$. Then $\frac{f(7)-f(6)}{7 - 6}=\frac{0 - 2}{1}=- 2<0$.

Step4: Analyze other intervals

For $[0,1]$, $f(0)=-1$ and $f(1) = 1$, $\frac{f(1)-f(0)}{1-0}=\frac{1-(-1)}{1}=2>0$. For $[3,4]$, $f(3) = 0$ and $f(4)=1$, $\frac{f(4)-f(3)}{4 - 3}=\frac{1-0}{1}=1>0$.

Answer:

The average rate of change is negative on the interval $[1,3]$ and also on the interval $[6,7]$.