begin by graphing f(x) = log x. use transformations of this graph to graph the given function. graph and…

begin by graphing f(x) = log x. use transformations of this graph to graph the given function. graph and give the equation of the asymptote. use the graphs to determine the functions domain and range. h(x) = log x - 8 graph h(x) = log x - 8. graph the asymptote of h(x) as a dashed line. use the graphing tool to graph the function. click to enlarge graph
Answer
Explanation:
Step1: Recall Parent Function
The parent function is ( f(x) = \log x ). Its vertical asymptote is ( x = 0 ) (y - axis), domain is ( (0, \infty) ), range is ( (-\infty, \infty) ).
Step2: Analyze Transformation for ( h(x) )
The function ( h(x)=\log x - 8 ) is a vertical shift of the parent function ( f(x)=\log x ) down by 8 units. Vertical shifts do not affect the vertical asymptote, domain, or the general shape related to the x - values.
Step3: Determine Asymptote
For the parent function ( y = \log x ), the vertical asymptote is ( x = 0 ). Since vertical shifts do not change the vertical asymptote, the vertical asymptote of ( h(x)=\log x - 8 ) is also ( x = 0 ).
Step4: Determine Domain
The domain of a logarithmic function ( y=\log_b(x) ) (here ( b = 10 ) for common logarithm) is the set of all positive real numbers. The vertical shift does not change the values of ( x ) for which the function is defined. So, the domain of ( h(x)=\log x - 8 ) is ( (0, \infty) ) (all real numbers greater than 0).
Step5: Determine Range
The range of the parent function ( y = \log x ) is ( (-\infty, \infty) ). A vertical shift down by 8 units still results in a range of all real numbers. So, the range of ( h(x)=\log x - 8 ) is ( (-\infty, \infty) ).
Answer:
- Asymptote: ( x = 0 )
- Domain: ( (0, \infty) )
- Range: ( (-\infty, \infty) ) (For graphing: The graph of ( h(x)=\log x - 8 ) is the graph of ( y = \log x ) shifted down 8 units. The vertical asymptote ( x = 0 ) is drawn as a dashed line.)