caleb went into a cave.\nthe light intensity (in candela per square meter, or cd/sq. m) as a function of…

caleb went into a cave.\nthe light intensity (in candela per square meter, or cd/sq. m) as a function of depth inside the cave (in m) is graphed.\nwhat is the approximate average rate at which the light intensity decreases, as caleb goes from a depth of 5 m to a depth of 14 m?\nchoose 1 answer:\n330 cd/sq. m per m\n390 cd/sq. m per m\n420 cd/sq. m per m\n480 cd/sq. m per m

caleb went into a cave.\nthe light intensity (in candela per square meter, or cd/sq. m) as a function of depth inside the cave (in m) is graphed.\nwhat is the approximate average rate at which the light intensity decreases, as caleb goes from a depth of 5 m to a depth of 14 m?\nchoose 1 answer:\n330 cd/sq. m per m\n390 cd/sq. m per m\n420 cd/sq. m per m\n480 cd/sq. m per m

Answer

Explanation:

Step1: Find the light intensity at (x = 5) and (x = 14)

From the graph, when (x = 5), (y\approx5000) (light - intensity at (5m) depth). When (x = 14), (y\approx1400) (light - intensity at (14m) depth).

Step2: Use the average rate of change formula

The average rate of change formula is (\frac{\Delta y}{\Delta x}=\frac{y_2 - y_1}{x_2 - x_1}). Here, (x_1 = 5), (y_1\approx5000), (x_2 = 14), (y_2\approx1400). Then (\frac{\Delta y}{\Delta x}=\frac{1400 - 5000}{14 - 5}=\frac{- 3600}{9}=- 400). The magnitude of the average rate of change (since we are talking about the rate at which it decreases) is approximately (400). The closest value to (400) among the options is (390) (due to possible graph - reading approximations).

Answer:

B. (390\ cd/sq.\ m\ per\ m)