how does f(x) = 9^x change over the interval from x = 3 to x = 4? a f(x) increases by 100% b f(x) increases…

how does f(x) = 9^x change over the interval from x = 3 to x = 4? a f(x) increases by 100% b f(x) increases by 800% c f(x) increases by 900% d f(x) increases by 1000%

how does f(x) = 9^x change over the interval from x = 3 to x = 4? a f(x) increases by 100% b f(x) increases by 800% c f(x) increases by 900% d f(x) increases by 1000%

Answer

Answer:

B. f(x) increases by 800%

Explanation:

Step1: Calculate f(3)

$f(3)=9^{3}=729$

Step2: Calculate f(4)

$f(4)=9^{4}=6561$

Step3: Calculate the increase amount

$6561 - 729=5832$

Step4: Calculate the percentage - increase

$\text{Percentage increase}=\frac{5832}{729}\times100% = 800%$