complete the paragraph. the function y = 2^x - 2 has a y - intercept at and a horizontal asymptote at.

Explanation:

Step1: Find y - intercept

Set $x = 0$ in $y=2^{x}-2$. Then $y=2^{0}-2$. Since $2^{0}=1$, we have $y = 1 - 2=-1$.

Step2: Find horizontal asymptote

As $x\to-\infty$, $2^{x}\to0$. So $y = 2^{x}-2\to0 - 2=-2$.

Answer:

The function $y = 2^{x}-2$ has a y - intercept at $-1$ and a horizontal asymptote at $y=-2$.