compute each of the following limits. use exact values.\nlim_{a→4^{-}}\\frac{|2a - 8|}{a…

compute each of the following limits. use exact values.\nlim_{a→4^{-}}\\frac{|2a - 8|}{a - 4}=2\nlim_{a→4^{+}}\\frac{|2a - 8|}{a - 4}=\nlim_{a→4}\\frac{|2a - 8|}{a - 4}=\nquestion help: video
Answer
Explanation:
Step1: Analyze left - hand limit
When $a\to4^{-}$, $2a - 8<0$, so $|2a - 8|=-(2a - 8)$. Then $\lim_{a\to4^{-}}\frac{|2a - 8|}{a - 4}=\lim_{a\to4^{-}}\frac{-(2a - 8)}{a - 4}=\lim_{a\to4^{-}}\frac{-2(a - 4)}{a - 4}=- 2$.
Step2: Analyze right - hand limit
When $a\to4^{+}$, $2a - 8>0$, so $|2a - 8|=2a - 8$. Then $\lim_{a\to4^{+}}\frac{|2a - 8|}{a - 4}=\lim_{a\to4^{+}}\frac{2a - 8}{a - 4}=\lim_{a\to4^{+}}\frac{2(a - 4)}{a - 4}=2$.
Step3: Analyze two - sided limit
Since $\lim_{a\to4^{-}}\frac{|2a - 8|}{a - 4}=-2$ and $\lim_{a\to4^{+}}\frac{|2a - 8|}{a - 4}=2$, $\lim_{a\to4}\frac{|2a - 8|}{a - 4}$ does not exist because the left - hand limit and the right - hand limit are not equal.
Answer:
$\lim_{a\to4^{-}}\frac{|2a - 8|}{a - 4}=-2$ $\lim_{a\to4^{+}}\frac{|2a - 8|}{a - 4}=2$ $\lim_{a\to4}\frac{|2a - 8|}{a - 4}$ does not exist