consider the following parametric equations:\n\n$x = \\frac{4t - 15}{2}$ and $y = 3 - t$\n\nstep 2 of 2…

consider the following parametric equations:\n\n$x = \\frac{4t - 15}{2}$ and $y = 3 - t$\n\nstep 2 of 2: plot the points that result from the integer t-values from zero to five on the graph. round the x - and y - coordinates of each point to one decimal place, if necessary.

consider the following parametric equations:\n\n$x = \\frac{4t - 15}{2}$ and $y = 3 - t$\n\nstep 2 of 2: plot the points that result from the integer t-values from zero to five on the graph. round the x - and y - coordinates of each point to one decimal place, if necessary.

Answer

Explanation:

Step1: Substitute (t = 0)

For (x=\frac{4t - 15}{2}), when (t = 0), (x=\frac{4\times0-15}{2}=\frac{- 15}{2}=-7.5). For (y = 3 - t), when (t = 0), (y=3-0 = 3). The point is ((-7.5,3)).

Step2: Substitute (t = 1)

For (x=\frac{4t - 15}{2}), when (t = 1), (x=\frac{4\times1-15}{2}=\frac{-11}{2}=-5.5). For (y = 3 - t), when (t = 1), (y=3 - 1=2). The point is ((-5.5,2)).

Step3: Substitute (t = 2)

For (x=\frac{4t - 15}{2}), when (t = 2), (x=\frac{4\times2-15}{2}=\frac{-7}{2}=-3.5). For (y = 3 - t), when (t = 2), (y=3-2 = 1). The point is ((-3.5,1)).

Step4: Substitute (t = 3)

For (x=\frac{4t - 15}{2}), when (t = 3), (x=\frac{4\times3-15}{2}=\frac{-3}{2}=-1.5). For (y = 3 - t), when (t = 3), (y=3-3=0). The point is ((-1.5,0)).

Step5: Substitute (t = 4)

For (x=\frac{4t - 15}{2}), when (t = 4), (x=\frac{4\times4-15}{2}=\frac{1}{2}=0.5). For (y = 3 - t), when (t = 4), (y=3 - 4=-1). The point is ((0.5,-1)).

Step6: Substitute (t = 5)

For (x=\frac{4t - 15}{2}), when (t = 5), (x=\frac{4\times5-15}{2}=\frac{5}{2}=2.5). For (y = 3 - t), when (t = 5), (y=3-5=-2). The point is ((2.5,-2)).

Answer:

The points are ((-7.5,3)), ((-5.5,2)), ((-3.5,1)), ((-1.5,0)), ((0.5,-1)), ((2.5,-2))