determine the amplitude and period of the following function without graphing. y = -\\frac{7}{9}\\cos(\\frac{…

determine the amplitude and period of the following function without graphing. y = -\\frac{7}{9}\\cos(\\frac{7}{6}x)\nfor the function given, the amplitude is \\frac{7}{9} (simplify your answer. type an exact answer, using pi as needed. use integers or fractions for any numbers in the expression.)\nfor the function given, \\omega = , so that the period = t = (simplify your answers. type exact answers, using pi as needed. use integers or fractions for any numbers in the expression.)
Answer
Explanation:
Step1: Recall amplitude formula
For a cosine function of the form $y = A\cos(\omega x)$, the amplitude is $|A|$. In the function $y=-\frac{7}{9}\cos(\frac{7}{6}x)$, $A =-\frac{7}{9}$, so the amplitude is $\left|-\frac{7}{9}\right|=\frac{7}{9}$.
Step2: Identify the value of $\omega$
For the function $y =-\frac{7}{9}\cos(\frac{7}{6}x)$, comparing with $y = A\cos(\omega x)$, we have $\omega=\frac{7}{6}$.
Step3: Recall period formula
The period $T$ of a cosine function $y = A\cos(\omega x)$ is given by $T=\frac{2\pi}{\omega}$. Substituting $\omega=\frac{7}{6}$ into the formula, we get $T=\frac{2\pi}{\frac{7}{6}}$.
Step4: Calculate the period
$T = 2\pi\times\frac{6}{7}=\frac{12\pi}{7}$.
Answer:
For the function given, $\omega=\frac{7}{6}$, so that the period $T=\frac{12\pi}{7}$