determine the amplitude or period as requested.\namplitude of ( y = -\frac{1}{5}sin x )\na. ( -\frac{1}{5}…

determine the amplitude or period as requested.\namplitude of ( y = -\frac{1}{5}sin x )\na. ( -\frac{1}{5} )\nb. ( \frac{1}{5} )\nc. 5\nd. ( \frac{pi}{5} )

determine the amplitude or period as requested.\namplitude of ( y = -\frac{1}{5}sin x )\na. ( -\frac{1}{5} )\nb. ( \frac{1}{5} )\nc. 5\nd. ( \frac{pi}{5} )

Answer

Explanation:

Step1: Recall the formula for the amplitude

For the function (y = A\sin x), the amplitude is given by (|A|).

Step2: Identify (A) in the given function

In the function (y =-\frac{1}{5}\sin x), (A =-\frac{1}{5}).

Step3: Calculate the amplitude

Using the formula (|A|), we substitute (A =-\frac{1}{5}). So, (|-\frac{1}{5}|=\frac{1}{5}).

Answer:

B. (\frac{1}{5})