determine the amplitude or period as requested.\nperiod of ( y = -\frac{1}{3}sin 2x )\na. ( -\frac{1}{3}…

determine the amplitude or period as requested.\nperiod of ( y = -\frac{1}{3}sin 2x )\na. ( -\frac{1}{3} )\nb. ( \frac{pi}{3} )\nc. ( \frac{1}{3} )\nd. ( pi )

determine the amplitude or period as requested.\nperiod of ( y = -\frac{1}{3}sin 2x )\na. ( -\frac{1}{3} )\nb. ( \frac{pi}{3} )\nc. ( \frac{1}{3} )\nd. ( pi )

Answer

Answer:

D. $\pi$

Explanation:

Step1: Recall the formula for the period of a sine function

The general form of a sine function is (y = A\sin(Bx + C)+D), and its period is (T=\frac{2\pi}{|B|}).

Step2: Identify the value of (B) in the given function

For the function (y =-\frac{1}{3}\sin(2x)), we have (B = 2).

Step3: Calculate the period

Using the formula (T=\frac{2\pi}{|B|}), substitute (B = 2) into it. Then (T=\frac{2\pi}{|2|}=\pi).