determine the following for the transformed cosine function shown whose period is 1,080 degrees.\nfrequency…

Answer:

Frequency: $\frac{1}{1080}$; $b$ in the equation: $\frac{1}{3}$

Explanation:

Step1: Recall frequency - period relationship

Frequency $f=\frac{1}{T}$, where $T$ is the period. Given $T = 1080$ degrees, so $f=\frac{1}{1080}$.

Step2: Recall period formula for cosine function

The general form of a cosine - function is $y = A\cos(bx - c)+d$, and the period $T=\frac{360^{\circ}}{|b|}$. Since $T = 1080^{\circ}$, then $1080=\frac{360}{|b|}$. Solving for $b$, we get $|b|=\frac{360}{1080}=\frac{1}{3}$. Assuming a standard form without reflections, $b=\frac{1}{3}$.