determine the following for the transformed cosine function shown whose period is 1,080 degrees.\nfrequency…

Explanation:

Step1: Recall general cosine - function form

The general form of a cosine function is $y = A\cos(bx - c)+d$, where the period $T=\frac{360^{\circ}}{|b|}$ (in degrees). We know $T = 1080^{\circ}$.

Step2: Solve for $b$

Since $T=\frac{360^{\circ}}{|b|}$, substituting $T = 1080^{\circ}$ gives $1080^{\circ}=\frac{360^{\circ}}{|b|}$. Cross - multiplying, we get $1080^{\circ}\times|b|=360^{\circ}$, so $|b|=\frac{360^{\circ}}{1080^{\circ}}=\frac{1}{3}$.

Step3: Determine the equation

Let's assume $A = 1$, $c = 0$, and $d = 0$ for the simplest form. The equation of the cosine function is $y=\cos(\frac{1}{3}x)$.

Answer:

$y=\cos(\frac{1}{3}x)$