differentiate the following function.\n\n$f(x)=e^{-4x + 1}$\n\n$\frac{d}{dx}(e^{-4x + 1})=square$
differentiate the following function.\n\n$f(x)=e^{-4x + 1}$\n\n$\frac{d}{dx}(e^{-4x + 1})=square$
Answer
Explanation:
Step1: Apply the chain rule
The chain rule states that if (y = e^{u}), then (\frac{dy}{dx}=e^{u}\cdot\frac{du}{dx}). Here (u=-4x + 1), so (\frac{du}{dx}=-4).
Step2: Calculate the derivative
(\frac{d}{dx}(e^{-4x + 1})=e^{-4x + 1}\cdot(-4))
Answer:
(-4e^{-4x + 1})