the distance of the hour hand from the ground can be represented using a sinusoidal function. at 12pm, the…

the distance of the hour hand from the ground can be represented using a sinusoidal function. at 12pm, the tip of the hour hand of a clock tower is 540 meters above the ground. at 6pm, the tip of the hour hand of the clock is 500 meters above the ground. determine the midline of the sinusoidal function.\n\n$y = 540$\n\n$y = 40$\n\n$y = 250$\n\n$y = 520$

the distance of the hour hand from the ground can be represented using a sinusoidal function. at 12pm, the tip of the hour hand of a clock tower is 540 meters above the ground. at 6pm, the tip of the hour hand of the clock is 500 meters above the ground. determine the midline of the sinusoidal function.\n\n$y = 540$\n\n$y = 40$\n\n$y = 250$\n\n$y = 520$

Answer

Explanation:

Step1: Recall mid - line formula

The mid - line of a sinusoidal function representing a periodic motion between a maximum value $y_{max}$ and a minimum value $y_{min}$ is given by $y=\frac{y_{max}+y_{min}}{2}$.

Step2: Identify maximum and minimum values

At 12 pm, the height is $y_{max} = 540$ meters (highest point), and at 6 pm, the height is $y_{min}=500$ meters (lowest point).

Step3: Calculate mid - line

$y=\frac{540 + 500}{2}=\frac{1040}{2}=520$.

Answer:

$y = 520$